(x+1)=(x-1)+x^2+3

Solution for (x+1)=(x-1)+x^2+3 equation:

(x+1)=(x-1)+x^2+3

We move all terms to the left:

(x+1)-((x-1)+x^2+3)=0

We get rid of parentheses

-((x-1)+x^2+3)+x+1=0


We calculate terms in parentheses: -((x-1)+x^2+3), so:

(x-1)+x^2+3

determiningTheFunctionDomain
x^2+(x-1)+3

We get rid of parentheses

x^2+x-1+3

We add all the numbers together, and all the variables

x^2+x+2

Back to the equation:

-(x^2+x+2)


We add all the numbers together, and all the variables

x-(x^2+x+2)+1=0

We get rid of parentheses

-x^2+x-x-2+1=0

We add all the numbers together, and all the variables

-1x^2-1=0

a = -1; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-1)·(-1)
Δ = -4
Delta is less than zero, so there is no solution for the equation